HomeAnalysis How many possible passwords with six to eight character long , each character is a letter or digit and each password must at least contains a digit ? February 03, 2021 0 Letp6=ofpasswordsofsixcharactersp7=ofpasswordsofsevencharactersp8=ofpasswordsofeightcharactersUsingsumruletherearep6+p7+p8passwords.p6=(#ofallpossiplestringsoflength6wherecharatersarelettersarenembers)−(#ofallpossiblestringsoflength6wherecharatersareonlyletters)=(36)6−(26)6=1867866560p7=(#ofallpossiplestringsoflength7wherecharatersarelettersarenembers)−(#ofallpossiblestringsoflength7wherecharatersareonlyletters)=(36)7−(26)7=70332353920p8=(#ofallpossiplestringsoflength8wherecharatersarelettersarenembers)−(#ofallpossiblestringsoflength8wherecharatersareonlyletters)=(36)8−(26)8=26122842880⇒p6+p7+p8⇒2684483063360Thefollowingiswronganswer…6(10)(36)5Wehavedoublecounting. Tags: Analysis Combinatorial Facebook Twitter