How to integrate sin sqrt(x)

$$\int sin\surd xdx$$

By Substitution $$\begin{array}{r}\text{ suppose }\Rightarrow z=\sqrt{x}\\ z^2=x\\ 2zdz=dx\end{array}$$ By Parts $$\begin{array}{lc}\text{ Let }\Rightarrow u=2z& dv=\sin z\\ du=2& v=-\cos z\\ -2z\cos z+4\int \cos z\mathrm{d}z\\ -2z\cos z+4\sin z+C\\ -2\sqrt{x}\cos \sqrt{x}+4\sin \sqrt{x}+C\end{array}$$