Homeintegration How to integrate (1+sqrt(x))^4 January 27, 2021 0 ∫1(1+x)4dx= By Substitution z=1+xdz=12xdx∫2(z−1)z4dz=∫2z−2z4dz=∫2zz4−∫2z4=−z−2+2z−33+c−(1+x)−2+2(1+x)−33+c Tags: integration Facebook Twitter