How To Integrate Ln x/x^2

 

$$\begin{array}{l}\int \frac{lnx}{x^2}\mathrm{d}x\\ \\ ByParts\\ Let\Rightarrow u=\ln xdv=\frac{1}{x^2}\\ du=\frac{1}{x}v=-\frac{1}{x}\\ -\frac{1}{x^{}}\ln x+\int \frac{1}{x^2}dx\\ -\frac{1}{x^{}}\ln x-\frac{1}{x^{}}+c\end{array}$$